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The Squeeze Theorem

Last updated Nov 24, 2021 Edit Source

When you take three funtions $f(x)$, $g(x)$ and $h(x)$ such that $f(x) \le g(x) \le h(x)$, but you can’t calculate the limit of the function $g(x)$ at a value $c$, you can simply calculate $\lim_{x\to c} f(x)$ and $\lim_{x\to c} h(x)$. The value of $\lim_{x\to c} g(x)$ must be between those values and if they are equal, then it must equal to that value as well. This method is particularly useful when dealing with the limits of periodical functions such as Trigonometric Functions, for instance, when calculating $\lim_{x\to 1}$ for $g(x) = x^2sin(\frac{\pi}{x})$ . Since the range of the sine function is $-1 \le sin(x) \le 1$, we can take $f(x) = -x^2$ and $g(x) = x^2$. Now, calculating the limit of both these we functions as x approaches 0, we find that they both equal 0, therefore the answer is 0.


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